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3(x+5)-5=2(x-3)
We move all terms to the left:
3(x+5)-5-(2(x-3))=0
We multiply parentheses
3x-(2(x-3))+15-5=0
We calculate terms in parentheses: -(2(x-3)), so:We add all the numbers together, and all the variables
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
3x-(2x-6)+10=0
We get rid of parentheses
3x-2x+6+10=0
We add all the numbers together, and all the variables
x+16=0
We move all terms containing x to the left, all other terms to the right
x=-16
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