3(x+5)+3x+1=3(x+5)+3x+1=-32

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Solution for 3(x+5)+3x+1=3(x+5)+3x+1=-32 equation: 



3(x+5)+3x+1=3(x+5)+3x+1=-32

We move all terms to the left:

3(x+5)+3x+1-(3(x+5)+3x+1)=0

We add all the numbers together, and all the variables

3x+3(x+5)-(3(x+5)+3x+1)+1=0

We multiply parentheses

3x+3x-(3(x+5)+3x+1)+15+1=0



We calculate terms in parentheses: -(3(x+5)+3x+1), so:

3(x+5)+3x+1

We add all the numbers together, and all the variables

3x+3(x+5)+1

We multiply parentheses

3x+3x+15+1

We add all the numbers together, and all the variables

6x+16

Back to the equation:

-(6x+16)



We add all the numbers together, and all the variables

6x-(6x+16)+16=0

We get rid of parentheses

6x-6x-16+16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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