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3(x+5)+3=9x+3(x+3)
We move all terms to the left:
3(x+5)+3-(9x+3(x+3))=0
We multiply parentheses
3x-(9x+3(x+3))+15+3=0
We calculate terms in parentheses: -(9x+3(x+3)), so:We add all the numbers together, and all the variables
9x+3(x+3)
We multiply parentheses
9x+3x+9
We add all the numbers together, and all the variables
12x+9
Back to the equation:
-(12x+9)
3x-(12x+9)+18=0
We get rid of parentheses
3x-12x-9+18=0
We add all the numbers together, and all the variables
-9x+9=0
We move all terms containing x to the left, all other terms to the right
-9x=-9
x=-9/-9
x=1
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