3(x+5)+2(6+x)=19+x

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Solution for 3(x+5)+2(6+x)=19+x equation: 



3(x+5)+2(6+x)=19+x

We move all terms to the left:

3(x+5)+2(6+x)-(19+x)=0

We add all the numbers together, and all the variables

3(x+5)+2(x+6)-(x+19)=0

We multiply parentheses

3x+2x-(x+19)+15+12=0

We get rid of parentheses

3x+2x-x-19+15+12=0

We add all the numbers together, and all the variables

4x+8=0

We move all terms containing x to the left, all other terms to the right

4x=-8

x=-8/4

x=-2

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