3(x+4)=7x+11-4x+1

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Solution for 3(x+4)=7x+11-4x+1 equation: 


Simplifying
3(x + 4) = 7x + 11 + -4x + 1

Reorder the terms:
3(4 + x) = 7x + 11 + -4x + 1
(4 * 3 + x * 3) = 7x + 11 + -4x + 1
(12 + 3x) = 7x + 11 + -4x + 1

Reorder the terms:
12 + 3x = 11 + 1 + 7x + -4x

Combine like terms: 11 + 1 = 12
12 + 3x = 12 + 7x + -4x

Combine like terms: 7x + -4x = 3x
12 + 3x = 12 + 3x

Add '-12' to each side of the equation.
12 + -12 + 3x = 12 + -12 + 3x

Combine like terms: 12 + -12 = 0
0 + 3x = 12 + -12 + 3x
3x = 12 + -12 + 3x

Combine like terms: 12 + -12 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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