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3(x+4)=2(2x-5)
We move all terms to the left:
3(x+4)-(2(2x-5))=0
We multiply parentheses
3x-(2(2x-5))+12=0
We calculate terms in parentheses: -(2(2x-5)), so:We get rid of parentheses
2(2x-5)
We multiply parentheses
4x-10
Back to the equation:
-(4x-10)
3x-4x+10+12=0
We add all the numbers together, and all the variables
-1x+22=0
We move all terms containing x to the left, all other terms to the right
-x=-22
x=-22/-1
x=+22
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