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3(x+4)=2(2x+6)-x
We move all terms to the left:
3(x+4)-(2(2x+6)-x)=0
We multiply parentheses
3x-(2(2x+6)-x)+12=0
We calculate terms in parentheses: -(2(2x+6)-x), so:We get rid of parentheses
2(2x+6)-x
We add all the numbers together, and all the variables
-1x+2(2x+6)
We multiply parentheses
-1x+4x+12
We add all the numbers together, and all the variables
3x+12
Back to the equation:
-(3x+12)
3x-3x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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