3(x+4)=-2(3x-2)+3x

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Solution for 3(x+4)=-2(3x-2)+3x equation: 



3(x+4)=-2(3x-2)+3x

We move all terms to the left:

3(x+4)-(-2(3x-2)+3x)=0

We multiply parentheses

3x-(-2(3x-2)+3x)+12=0



We calculate terms in parentheses: -(-2(3x-2)+3x), so:

-2(3x-2)+3x

We add all the numbers together, and all the variables

3x-2(3x-2)

We multiply parentheses

3x-6x+4

We add all the numbers together, and all the variables

-3x+4

Back to the equation:

-(-3x+4)



We get rid of parentheses

3x+3x-4+12=0

We add all the numbers together, and all the variables

6x+8=0

We move all terms containing x to the left, all other terms to the right

6x=-8

x=-8/6

x=-1+1/3

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