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3(x+4)=-2(2x+11)+4
We move all terms to the left:
3(x+4)-(-2(2x+11)+4)=0
We multiply parentheses
3x-(-2(2x+11)+4)+12=0
We calculate terms in parentheses: -(-2(2x+11)+4), so:We get rid of parentheses
-2(2x+11)+4
We multiply parentheses
-4x-22+4
We add all the numbers together, and all the variables
-4x-18
Back to the equation:
-(-4x-18)
3x+4x+18+12=0
We add all the numbers together, and all the variables
7x+30=0
We move all terms containing x to the left, all other terms to the right
7x=-30
x=-30/7
x=-4+2/7
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