3(x+4)2+7=13

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Solution for 3(x+4)2+7=13 equation: 



3(x+4)2+7=13

We move all terms to the left:

3(x+4)2+7-(13)=0

We add all the numbers together, and all the variables

3(x+4)2-6=0

We multiply parentheses

6x+24-6=0

We add all the numbers together, and all the variables

6x+18=0

We move all terms containing x to the left, all other terms to the right

6x=-18

x=-18/6

x=-3

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