3(x+4)-8=4(2x-5)+4

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Solution for 3(x+4)-8=4(2x-5)+4 equation: 



3(x+4)-8=4(2x-5)+4

We move all terms to the left:

3(x+4)-8-(4(2x-5)+4)=0

We multiply parentheses

3x-(4(2x-5)+4)+12-8=0



We calculate terms in parentheses: -(4(2x-5)+4), so:

4(2x-5)+4

We multiply parentheses

8x-20+4

We add all the numbers together, and all the variables

8x-16

Back to the equation:

-(8x-16)



We add all the numbers together, and all the variables

3x-(8x-16)+4=0

We get rid of parentheses

3x-8x+16+4=0

We add all the numbers together, and all the variables

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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