3(x+4)-8=2(3x-5)-(x-8)

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Solution for 3(x+4)-8=2(3x-5)-(x-8) equation: 



3(x+4)-8=2(3x-5)-(x-8)

We move all terms to the left:

3(x+4)-8-(2(3x-5)-(x-8))=0

We multiply parentheses

3x-(2(3x-5)-(x-8))+12-8=0



We calculate terms in parentheses: -(2(3x-5)-(x-8)), so:

2(3x-5)-(x-8)

We multiply parentheses

6x-(x-8)-10

We get rid of parentheses

6x-x+8-10

We add all the numbers together, and all the variables

5x-2

Back to the equation:

-(5x-2)



We add all the numbers together, and all the variables

3x-(5x-2)+4=0

We get rid of parentheses

3x-5x+2+4=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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