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3(x+4)-5=x+2(x-7)
We move all terms to the left:
3(x+4)-5-(x+2(x-7))=0
We multiply parentheses
3x-(x+2(x-7))+12-5=0
We calculate terms in parentheses: -(x+2(x-7)), so:We add all the numbers together, and all the variables
x+2(x-7)
We multiply parentheses
x+2x-14
We add all the numbers together, and all the variables
3x-14
Back to the equation:
-(3x-14)
3x-(3x-14)+7=0
We get rid of parentheses
3x-3x+14+7=0
We add all the numbers together, and all the variables
21!=0
There is no solution for this equation
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