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3(x+4)-5=2(x+4)+x
We move all terms to the left:
3(x+4)-5-(2(x+4)+x)=0
We multiply parentheses
3x-(2(x+4)+x)+12-5=0
We calculate terms in parentheses: -(2(x+4)+x), so:We add all the numbers together, and all the variables
2(x+4)+x
We add all the numbers together, and all the variables
x+2(x+4)
We multiply parentheses
x+2x+8
We add all the numbers together, and all the variables
3x+8
Back to the equation:
-(3x+8)
3x-(3x+8)+7=0
We get rid of parentheses
3x-3x-8+7=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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