3(x+4)-4=-2(x+4)+x

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Solution for 3(x+4)-4=-2(x+4)+x equation: 



3(x+4)-4=-2(x+4)+x

We move all terms to the left:

3(x+4)-4-(-2(x+4)+x)=0

We multiply parentheses

3x-(-2(x+4)+x)+12-4=0



We calculate terms in parentheses: -(-2(x+4)+x), so:

-2(x+4)+x

We add all the numbers together, and all the variables

x-2(x+4)

We multiply parentheses

x-2x-8

We add all the numbers together, and all the variables

-1x-8

Back to the equation:

-(-1x-8)



We add all the numbers together, and all the variables

3x-(-1x-8)+8=0

We get rid of parentheses

3x+1x+8+8=0

We add all the numbers together, and all the variables

4x+16=0

We move all terms containing x to the left, all other terms to the right

4x=-16

x=-16/4

x=-4

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