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3(x+4)-2x=2/3(x-5)+4
We move all terms to the left:
3(x+4)-2x-(2/3(x-5)+4)=0
Domain of the equation: 3(x-5)+4)!=0We add all the numbers together, and all the variables
x∈R
-2x+3(x+4)-(2/3(x-5)+4)=0
We multiply parentheses
-2x+3x-(2/3(x-5)+4)+12=0
We multiply all the terms by the denominator
-2x*3(x-5)+4)+3x*3(x-5)+4)-(2+12*3(x-5)+4)=0
We add all the numbers together, and all the variables
-2x*3(x-5)+4)+3x*3(x-5)+4)-(2+12*3(x=0
Wy multiply elements
-6x^2(x+4)+3x*3(x-5)+12*3(x+4)-(2=0
We add all the numbers together, and all the variables
-6x^2(x+4)+3x*3(x-5)+12*3(x+4)=0
Wy multiply elements
-6x^2(x+4)+9x^2(x+36x(x=0
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