3(x+4)-282+2x=3(x-6x+12+2

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Solution for 3(x+4)-282+2x=3(x-6x+12+2 equation: 



3(x+4)-282+2x=3(x-6x+12+2

We move all terms to the left:

3(x+4)-282+2x-(3(x-6x+12+2)=0

We add all the numbers together, and all the variables

3(x+4)+2x-(3(-5x+14)-282=0

We add all the numbers together, and all the variables

2x+3(x+4)-(3(-5x+14)-282=0

We multiply parentheses

2x+3x-(3(-5x+14)-282+12=0

We add all the numbers together, and all the variables

5x-(3(-5x+14)-282+12=0

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