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3(x+4)+2x=(x-2)-4
We move all terms to the left:
3(x+4)+2x-((x-2)-4)=0
We add all the numbers together, and all the variables
2x+3(x+4)-((x-2)-4)=0
We multiply parentheses
2x+3x-((x-2)-4)+12=0
We calculate terms in parentheses: -((x-2)-4), so:We add all the numbers together, and all the variables
(x-2)-4
We get rid of parentheses
x-2-4
We add all the numbers together, and all the variables
x-6
Back to the equation:
-(x-6)
5x-(x-6)+12=0
We get rid of parentheses
5x-x+6+12=0
We add all the numbers together, and all the variables
4x+18=0
We move all terms containing x to the left, all other terms to the right
4x=-18
x=-18/4
x=-4+1/2
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