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3(x+4)+2=6x-3(-4+x)
We move all terms to the left:
3(x+4)+2-(6x-3(-4+x))=0
We add all the numbers together, and all the variables
3(x+4)-(6x-3(x-4))+2=0
We multiply parentheses
3x-(6x-3(x-4))+12+2=0
We calculate terms in parentheses: -(6x-3(x-4)), so:We add all the numbers together, and all the variables
6x-3(x-4)
We multiply parentheses
6x-3x+12
We add all the numbers together, and all the variables
3x+12
Back to the equation:
-(3x+12)
3x-(3x+12)+14=0
We get rid of parentheses
3x-3x-12+14=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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