3(x+4)+2(x+2)=41

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Solution for 3(x+4)+2(x+2)=41 equation:


Simplifying
3(x + 4) + 2(x + 2) = 41

Reorder the terms:
3(4 + x) + 2(x + 2) = 41
(4 * 3 + x * 3) + 2(x + 2) = 41
(12 + 3x) + 2(x + 2) = 41

Reorder the terms:
12 + 3x + 2(2 + x) = 41
12 + 3x + (2 * 2 + x * 2) = 41
12 + 3x + (4 + 2x) = 41

Reorder the terms:
12 + 4 + 3x + 2x = 41

Combine like terms: 12 + 4 = 16
16 + 3x + 2x = 41

Combine like terms: 3x + 2x = 5x
16 + 5x = 41

Solving
16 + 5x = 41

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + 5x = 41 + -16

Combine like terms: 16 + -16 = 0
0 + 5x = 41 + -16
5x = 41 + -16

Combine like terms: 41 + -16 = 25
5x = 25

Divide each side by '5'.
x = 5

Simplifying
x = 5

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