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3(x+4)+1=2(x-1)
We move all terms to the left:
3(x+4)+1-(2(x-1))=0
We multiply parentheses
3x-(2(x-1))+12+1=0
We calculate terms in parentheses: -(2(x-1)), so:We add all the numbers together, and all the variables
2(x-1)
We multiply parentheses
2x-2
Back to the equation:
-(2x-2)
3x-(2x-2)+13=0
We get rid of parentheses
3x-2x+2+13=0
We add all the numbers together, and all the variables
x+15=0
We move all terms containing x to the left, all other terms to the right
x=-15
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