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3(x+4)+1=2(x+5)-8
We move all terms to the left:
3(x+4)+1-(2(x+5)-8)=0
We multiply parentheses
3x-(2(x+5)-8)+12+1=0
We calculate terms in parentheses: -(2(x+5)-8), so:We add all the numbers together, and all the variables
2(x+5)-8
We multiply parentheses
2x+10-8
We add all the numbers together, and all the variables
2x+2
Back to the equation:
-(2x+2)
3x-(2x+2)+13=0
We get rid of parentheses
3x-2x-2+13=0
We add all the numbers together, and all the variables
x+11=0
We move all terms containing x to the left, all other terms to the right
x=-11
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