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3(x+4)+-2=2(2x+5)+x
We move all terms to the left:
3(x+4)+-2-(2(2x+5)+x)=0
We add all the numbers together, and all the variables
3(x+4)-(2(2x+5)+x)=0
We multiply parentheses
3x-(2(2x+5)+x)+12=0
We calculate terms in parentheses: -(2(2x+5)+x), so:We get rid of parentheses
2(2x+5)+x
We add all the numbers together, and all the variables
x+2(2x+5)
We multiply parentheses
x+4x+10
We add all the numbers together, and all the variables
5x+10
Back to the equation:
-(5x+10)
3x-5x-10+12=0
We add all the numbers together, and all the variables
-2x+2=0
We move all terms containing x to the left, all other terms to the right
-2x=-2
x=-2/-2
x=1
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