3(x+4(x-2))=2(x-1)-3(6-x)

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Solution for 3(x+4(x-2))=2(x-1)-3(6-x) equation: 



3(x+4(x-2))=2(x-1)-3(6-x)

We move all terms to the left:

3(x+4(x-2))-(2(x-1)-3(6-x))=0

We add all the numbers together, and all the variables

3(x+4(x-2))-(2(x-1)-3(-1x+6))=0



We calculate terms in parentheses: -(2(x-1)-3(-1x+6)), so:

2(x-1)-3(-1x+6)

We multiply parentheses

2x+3x-2-18

We add all the numbers together, and all the variables

5x-20

Back to the equation:

-(5x-20)



We get rid of parentheses

3(x+4(x-2))-5x+20=0

We add all the numbers together, and all the variables

-5x+3(x+4(x-2))+20=0

We move all terms containing x to the left, all other terms to the right

-5x+3(x+4(x-2))=-20

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