3(x+3)=9+9x+2(-3x)

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Solution for 3(x+3)=9+9x+2(-3x) equation: 



3(x+3)=9+9x+2(-3x)

We move all terms to the left:

3(x+3)-(9+9x+2(-3x))=0

We multiply parentheses

3x-(9+9x+2(-3x))+9=0



We calculate terms in parentheses: -(9+9x+2(-3x)), so:

9+9x+2(-3x)

determiningTheFunctionDomain
9x+2(-3x)+9

We multiply parentheses

9x-6x+9

We add all the numbers together, and all the variables

3x+9

Back to the equation:

-(3x+9)



We get rid of parentheses

3x-3x-9+9=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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