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3(x+3)=7(4-x)
We move all terms to the left:
3(x+3)-(7(4-x))=0
We add all the numbers together, and all the variables
3(x+3)-(7(-1x+4))=0
We multiply parentheses
3x-(7(-1x+4))+9=0
We calculate terms in parentheses: -(7(-1x+4)), so:We get rid of parentheses
7(-1x+4)
We multiply parentheses
-7x+28
Back to the equation:
-(-7x+28)
3x+7x-28+9=0
We add all the numbers together, and all the variables
10x-19=0
We move all terms containing x to the left, all other terms to the right
10x=19
x=19/10
x=1+9/10
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