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3(x+3)/15x-30x=12
We move all terms to the left:
3(x+3)/15x-30x-(12)=0
Domain of the equation: 15x!=0We add all the numbers together, and all the variables
x!=0/15
x!=0
x∈R
-30x+3(x+3)/15x-12=0
We multiply all the terms by the denominator
-30x*15x+3(x+3)-12*15x=0
We multiply parentheses
-30x*15x+3x-12*15x+9=0
Wy multiply elements
-450x^2+3x-180x+9=0
We add all the numbers together, and all the variables
-450x^2-177x+9=0
a = -450; b = -177; c = +9;
Δ = b2-4ac
Δ = -1772-4·(-450)·9
Δ = 47529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{47529}=\sqrt{9*5281}=\sqrt{9}*\sqrt{5281}=3\sqrt{5281}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-177)-3\sqrt{5281}}{2*-450}=\frac{177-3\sqrt{5281}}{-900} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-177)+3\sqrt{5281}}{2*-450}=\frac{177+3\sqrt{5281}}{-900} $
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