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3(x+3)-5(x-3)=2x+5(6-2x)
We move all terms to the left:
3(x+3)-5(x-3)-(2x+5(6-2x))=0
We add all the numbers together, and all the variables
3(x+3)-5(x-3)-(2x+5(-2x+6))=0
We multiply parentheses
3x-5x-(2x+5(-2x+6))+9+15=0
We calculate terms in parentheses: -(2x+5(-2x+6)), so:We add all the numbers together, and all the variables
2x+5(-2x+6)
We multiply parentheses
2x-10x+30
We add all the numbers together, and all the variables
-8x+30
Back to the equation:
-(-8x+30)
-2x-(-8x+30)+24=0
We get rid of parentheses
-2x+8x-30+24=0
We add all the numbers together, and all the variables
6x-6=0
We move all terms containing x to the left, all other terms to the right
6x=6
x=6/6
x=1
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