3(x+3)-4(-2+x)=19

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Solution for 3(x+3)-4(-2+x)=19 equation: 



3(x+3)-4(-2+x)=19

We move all terms to the left:

3(x+3)-4(-2+x)-(19)=0

We add all the numbers together, and all the variables

3(x+3)-4(x-2)-19=0

We multiply parentheses

3x-4x+9+8-19=0

We add all the numbers together, and all the variables

-1x-2=0

We move all terms containing x to the left, all other terms to the right

-x=2

x=2/-1

x=-2

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