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3(x+3)-2x+1/2=05
We move all terms to the left:
3(x+3)-2x+1/2-(05)=0
determiningTheFunctionDomain 3(x+3)-2x-05+1/2=0
We add all the numbers together, and all the variables
-2x+3(x+3)-5+1/2=0
We multiply parentheses
-2x+3x+9-5+1/2=0
We multiply all the terms by the denominator
-2x*2+3x*2+1+9*2-5*2=0
We add all the numbers together, and all the variables
-2x*2+3x*2+9=0
Wy multiply elements
-4x+6x+9=0
We add all the numbers together, and all the variables
2x+9=0
We move all terms containing x to the left, all other terms to the right
2x=-9
x=-9/2
x=-4+1/2
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