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3(x+3)-2(x+1)=8
We move all terms to the left:
3(x+3)-2(x+1)-(8)=0
We multiply parentheses
3x-2x+9-2-8=0
We add all the numbers together, and all the variables
x-1=0
We move all terms containing x to the left, all other terms to the right
x=1
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