3(x+3)+5=4(x-4)

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Solution for 3(x+3)+5=4(x-4) equation: 



3(x+3)+5=4(x-4)

We move all terms to the left:

3(x+3)+5-(4(x-4))=0

We multiply parentheses

3x-(4(x-4))+9+5=0



We calculate terms in parentheses: -(4(x-4)), so:

4(x-4)

We multiply parentheses

4x-16

Back to the equation:

-(4x-16)



We add all the numbers together, and all the variables

3x-(4x-16)+14=0

We get rid of parentheses

3x-4x+16+14=0

We add all the numbers together, and all the variables

-1x+30=0

We move all terms containing x to the left, all other terms to the right

-x=-30

x=-30/-1

x=+30

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