3(x+2)=x+5-3(x+2)

Solution for 3(x+2)=x+5-3(x+2) equation:

3(x+2)=x+5-3(x+2)

We move all terms to the left:

3(x+2)-(x+5-3(x+2))=0

We multiply parentheses

3x-(x+5-3(x+2))+6=0


We calculate terms in parentheses: -(x+5-3(x+2)), so:

x+5-3(x+2)

determiningTheFunctionDomain
x-3(x+2)+5

We multiply parentheses

x-3x-6+5

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)


We get rid of parentheses

3x+2x+1+6=0

We add all the numbers together, and all the variables

5x+7=0

We move all terms containing x to the left, all other terms to the right

5x=-7

x=-7/5

x=-1+2/5