3(x+2)=8-2(x-1)

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Solution for 3(x+2)=8-2(x-1) equation: 



3(x+2)=8-2(x-1)

We move all terms to the left:

3(x+2)-(8-2(x-1))=0

We multiply parentheses

3x-(8-2(x-1))+6=0



We calculate terms in parentheses: -(8-2(x-1)), so:

8-2(x-1)

determiningTheFunctionDomain
-2(x-1)+8

We multiply parentheses

-2x+2+8

We add all the numbers together, and all the variables

-2x+10

Back to the equation:

-(-2x+10)



We get rid of parentheses

3x+2x-10+6=0

We add all the numbers together, and all the variables

5x-4=0

We move all terms containing x to the left, all other terms to the right

5x=4

x=4/5

x=4/5

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