3(x+2)=8(x+1)

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Solution for 3(x+2)=8(x+1) equation: 



3(x+2)=8(x+1)

We move all terms to the left:

3(x+2)-(8(x+1))=0

We multiply parentheses

3x-(8(x+1))+6=0



We calculate terms in parentheses: -(8(x+1)), so:

8(x+1)

We multiply parentheses

8x+8

Back to the equation:

-(8x+8)



We get rid of parentheses

3x-8x-8+6=0

We add all the numbers together, and all the variables

-5x-2=0

We move all terms containing x to the left, all other terms to the right

-5x=2

x=2/-5

x=-2/5

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