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3(x+2)=5x-2(2x-11)
We move all terms to the left:
3(x+2)-(5x-2(2x-11))=0
We multiply parentheses
3x-(5x-2(2x-11))+6=0
We calculate terms in parentheses: -(5x-2(2x-11)), so:We get rid of parentheses
5x-2(2x-11)
We multiply parentheses
5x-4x+22
We add all the numbers together, and all the variables
x+22
Back to the equation:
-(x+22)
3x-x-22+6=0
We add all the numbers together, and all the variables
2x-16=0
We move all terms containing x to the left, all other terms to the right
2x=16
x=16/2
x=8
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