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3(x+2)=5-(2x+1)
We move all terms to the left:
3(x+2)-(5-(2x+1))=0
We multiply parentheses
3x-(5-(2x+1))+6=0
We calculate terms in parentheses: -(5-(2x+1)), so:We get rid of parentheses
5-(2x+1)
determiningTheFunctionDomain -(2x+1)+5
We get rid of parentheses
-2x-1+5
We add all the numbers together, and all the variables
-2x+4
Back to the equation:
-(-2x+4)
3x+2x-4+6=0
We add all the numbers together, and all the variables
5x+2=0
We move all terms containing x to the left, all other terms to the right
5x=-2
x=-2/5
x=-2/5
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