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3(x+2)=5(x-3)
We move all terms to the left:
3(x+2)-(5(x-3))=0
We multiply parentheses
3x-(5(x-3))+6=0
We calculate terms in parentheses: -(5(x-3)), so:We get rid of parentheses
5(x-3)
We multiply parentheses
5x-15
Back to the equation:
-(5x-15)
3x-5x+15+6=0
We add all the numbers together, and all the variables
-2x+21=0
We move all terms containing x to the left, all other terms to the right
-2x=-21
x=-21/-2
x=10+1/2
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