3(x+2)=5(2x+1)+8

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Solution for 3(x+2)=5(2x+1)+8 equation: 



3(x+2)=5(2x+1)+8

We move all terms to the left:

3(x+2)-(5(2x+1)+8)=0

We multiply parentheses

3x-(5(2x+1)+8)+6=0



We calculate terms in parentheses: -(5(2x+1)+8), so:

5(2x+1)+8

We multiply parentheses

10x+5+8

We add all the numbers together, and all the variables

10x+13

Back to the equation:

-(10x+13)



We get rid of parentheses

3x-10x-13+6=0

We add all the numbers together, and all the variables

-7x-7=0

We move all terms containing x to the left, all other terms to the right

-7x=7

x=7/-7

x=-1

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