3(x+2)=4(x-6)+(x+5)

Solution for 3(x+2)=4(x-6)+(x+5) equation:

3(x+2)=4(x-6)+(x+5)

We move all terms to the left:

3(x+2)-(4(x-6)+(x+5))=0

We multiply parentheses

3x-(4(x-6)+(x+5))+6=0


We calculate terms in parentheses: -(4(x-6)+(x+5)), so:

4(x-6)+(x+5)

We multiply parentheses

4x+(x+5)-24

We get rid of parentheses

4x+x+5-24

We add all the numbers together, and all the variables

5x-19

Back to the equation:

-(5x-19)


We get rid of parentheses

3x-5x+19+6=0

We add all the numbers together, and all the variables

-2x+25=0

We move all terms containing x to the left, all other terms to the right

-2x=-25

x=-25/-2

x=12+1/2