3(x+2)=4(x+1)-5

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Solution for 3(x+2)=4(x+1)-5 equation: 



3(x+2)=4(x+1)-5

We move all terms to the left:

3(x+2)-(4(x+1)-5)=0

We multiply parentheses

3x-(4(x+1)-5)+6=0



We calculate terms in parentheses: -(4(x+1)-5), so:

4(x+1)-5

We multiply parentheses

4x+4-5

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)



We get rid of parentheses

3x-4x+1+6=0

We add all the numbers together, and all the variables

-1x+7=0

We move all terms containing x to the left, all other terms to the right

-x=-7

x=-7/-1

x=+7

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