3(x+2)=4(x+1)+7

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Solution for 3(x+2)=4(x+1)+7 equation: 



3(x+2)=4(x+1)+7

We move all terms to the left:

3(x+2)-(4(x+1)+7)=0

We multiply parentheses

3x-(4(x+1)+7)+6=0



We calculate terms in parentheses: -(4(x+1)+7), so:

4(x+1)+7

We multiply parentheses

4x+4+7

We add all the numbers together, and all the variables

4x+11

Back to the equation:

-(4x+11)



We get rid of parentheses

3x-4x-11+6=0

We add all the numbers together, and all the variables

-1x-5=0

We move all terms containing x to the left, all other terms to the right

-x=5

x=5/-1

x=-5

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