3(x+2)=2(3x+3)

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Solution for 3(x+2)=2(3x+3) equation: 



3(x+2)=2(3x+3)

We move all terms to the left:

3(x+2)-(2(3x+3))=0

We multiply parentheses

3x-(2(3x+3))+6=0



We calculate terms in parentheses: -(2(3x+3)), so:

2(3x+3)

We multiply parentheses

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

3x-6x-6+6=0

We add all the numbers together, and all the variables

-3x=0

x=0/-3

x=0

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