3(x+2)=13+4(x-2)

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Solution for 3(x+2)=13+4(x-2) equation: 



3(x+2)=13+4(x-2)

We move all terms to the left:

3(x+2)-(13+4(x-2))=0

We multiply parentheses

3x-(13+4(x-2))+6=0



We calculate terms in parentheses: -(13+4(x-2)), so:

13+4(x-2)

determiningTheFunctionDomain
4(x-2)+13

We multiply parentheses

4x-8+13

We add all the numbers together, and all the variables

4x+5

Back to the equation:

-(4x+5)



We get rid of parentheses

3x-4x-5+6=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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