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3(x+2)=-2(-x-5)
We move all terms to the left:
3(x+2)-(-2(-x-5))=0
We add all the numbers together, and all the variables
3(x+2)-(-2(-1x-5))=0
We multiply parentheses
3x-(-2(-1x-5))+6=0
We calculate terms in parentheses: -(-2(-1x-5)), so:We get rid of parentheses
-2(-1x-5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
3x-2x-10+6=0
We add all the numbers together, and all the variables
x-4=0
We move all terms containing x to the left, all other terms to the right
x=4
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