3(x+2)3x=36

Solution for 3(x+2)3x=36 equation:

3(x+2)3x=36

We move all terms to the left:

3(x+2)3x-(36)=0

We multiply parentheses

9x^2+18x-36=0

a = 9; b = 18; c = -36;
Δ = b2-4ac
Δ = 182-4·9·(-36)
Δ = 1620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1620}=\sqrt{324*5}=\sqrt{324}*\sqrt{5}=18\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18\sqrt{5}}{2*9}=\frac{-18-18\sqrt{5}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18\sqrt{5}}{2*9}=\frac{-18+18\sqrt{5}}{18}
$