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3(x+2)-5=4x-(2x+3)
We move all terms to the left:
3(x+2)-5-(4x-(2x+3))=0
We multiply parentheses
3x-(4x-(2x+3))+6-5=0
We calculate terms in parentheses: -(4x-(2x+3)), so:We add all the numbers together, and all the variables
4x-(2x+3)
We get rid of parentheses
4x-2x-3
We add all the numbers together, and all the variables
2x-3
Back to the equation:
-(2x-3)
3x-(2x-3)+1=0
We get rid of parentheses
3x-2x+3+1=0
We add all the numbers together, and all the variables
x+4=0
We move all terms containing x to the left, all other terms to the right
x=-4
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