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3(x+2)-5(2-x)=4(2x-1)
We move all terms to the left:
3(x+2)-5(2-x)-(4(2x-1))=0
We add all the numbers together, and all the variables
3(x+2)-5(-1x+2)-(4(2x-1))=0
We multiply parentheses
3x+5x-(4(2x-1))+6-10=0
We calculate terms in parentheses: -(4(2x-1)), so:We add all the numbers together, and all the variables
4(2x-1)
We multiply parentheses
8x-4
Back to the equation:
-(8x-4)
8x-(8x-4)-4=0
We get rid of parentheses
8x-8x+4-4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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