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3(x+2)-2x=-2(x-3)+3
We move all terms to the left:
3(x+2)-2x-(-2(x-3)+3)=0
We add all the numbers together, and all the variables
-2x+3(x+2)-(-2(x-3)+3)=0
We multiply parentheses
-2x+3x-(-2(x-3)+3)+6=0
We calculate terms in parentheses: -(-2(x-3)+3), so:We add all the numbers together, and all the variables
-2(x-3)+3
We multiply parentheses
-2x+6+3
We add all the numbers together, and all the variables
-2x+9
Back to the equation:
-(-2x+9)
x-(-2x+9)+6=0
We get rid of parentheses
x+2x-9+6=0
We add all the numbers together, and all the variables
3x-3=0
We move all terms containing x to the left, all other terms to the right
3x=3
x=3/3
x=1
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