3(x+2)-2(x+1)+6(x-2)=15

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Solution for 3(x+2)-2(x+1)+6(x-2)=15 equation: 



3(x+2)-2(x+1)+6(x-2)=15

We move all terms to the left:

3(x+2)-2(x+1)+6(x-2)-(15)=0

We multiply parentheses

3x-2x+6x+6-2-12-15=0

We add all the numbers together, and all the variables

7x-23=0

We move all terms containing x to the left, all other terms to the right

7x=23

x=23/7

x=3+2/7

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